Why isn't (“Maya” == “Maya”) true in C++?

Question

Any idea why I get \"Maya is not Maya\" as a result of this code?

if (\"Maya\" == \"Maya\") 
   printf(\"Maya is Maya \\n\");
else
   printf(\"Maya is not Ma         


        

Answer 1

What you are doing is comparing the address of one string with the address of another. Depending on the compiler and its settings, sometimes the identical literal strings will have the same address, and sometimes they won't (as apparently you found).