Why isn't (“Maya” == “Maya”) true in C++?

Question

Any idea why I get \"Maya is not Maya\" as a result of this code?

if (\"Maya\" == \"Maya\") 
   printf(\"Maya is Maya \\n\");
else
   printf(\"Maya is not Ma         


        

Answer 1

You are not comparing strings, you are comparing pointer address equality.

To be more explicit -

"foo baz bar" implicitly defines an anonymous const char[m]. It is implementation-defined as to whether identical anonymous const char[m] will point to the same location in memory(a concept referred to as interning).

The function you want - in C - is strmp(char*, char*), which returns 0 on equality.

Or, in C++, what you might do is

#include

std::string s1 = "foo"

std::string s2 = "bar"

and then compare s1 vs. s2 with the == operator, which is defined in an intuitive fashion for strings.