Pass a function by reference in PHP

Question

Is it possible to pass functions by reference?

Something like this:

function call($func){
    $func();
}

function test(){
    echo \"hello world!\";         


        

Answer 1

In PHP 5.4.4 (haven't tested lower or other versions), you can do exactly as you suggested.

Take this as an example:

function test ($func) {
    $func('moo');
}

function aFunctionToPass ($str) {
    echo $str;
}

test('aFunctionToPass');

The script will echo "moo" as if you called "aFunctionToPass" directly.