[[1, \'34\', \'44\'], [1, \'40\', \'30\', \'41\'], [1, \'41\', \'40\', \'42\'], [1, \'42\', \'41\', \'43\'], [1, \'43\', \'42\', \'44\'], [1, \'44\', \'34\', \'43\']
The itertools module makes short work of this problem:
>>> from itertools import chain
>>> list(set(chain.from_iterable(d)))
[1, '41', '42', '43', '40', '34', '30', '44']
Another way to do it is to unpack the list into separate arguments for union():
>>> list(set().union(*d))
[1, '41', '42', '43', '40', '34', '30', '44']
The latter way eliminates all duplicates and doesn't require that the inputs first be converted to sets. Also, it doesn't require an import.