I\'m under the impression that these two commands result in the same end, namely incrementing X by 1 but that the latter is probably more efficient.
If this is not c
On x86, if x is in register eax, they will both result in something like
inc eax;
So you're right, after some compilation stage, the IL will be the same.
There's a whole class of questions like this that can be answered with "trust your optimizer."
The famous myth is that
x++;
is less efficient than
++x;
because it has to store a temporary value. If you never use the temporary value, the optimizer will remove that store.