Setting environment variable for one program call in bash using env

Question

I am trying to invoke a shell command with a modified environment via the command env.

According to the manual

env HELLO=\'Hello World\'         


        

Answer 1

It's because in your first case, your current shell expands the $HELLO variable before running the commands. And there's no HELLO variable set in your current shell.

env HELLO='Hello World' echo $HELLO

will do this:

• expand any variables given, in this case $HELLO
• run env with the 3 arguments 'HELLO=Hello World', 'echo' and '' (an empty string, since there's no HELLO variable set in the current shell)
• The env command will run and set the HELLO='Hello World' in its environment
• env will run echo with the argument '' (an empty string)

As you see, the current shell expanded the $HELLO variable, which isn't set.

HELLO='Hello World' bash -c 'echo $HELLO'

will do this:

• set the variable HELLO='Hello World for the following command
• run bash with the 2 arguments '-c' and 'echo $HELLO'
• since the last argument is enclosed in single quotes, nothing inside it is expanded
• the new bash in turn will run the command echo $HELLO
• To run echo $HELLO in the new bash sub-shell, bash first expands anything it can, $HELLO in this case, and the parent shell set that to Hello World for us.
• The subshell runs echo 'Hello World'

If you tried to do e.g. this:

env HELLO='Hello World' echo '$HELLO'

• The current shell would expand anything it can, which is nothing since $HELLO is enclosed in single quotes
• run env with the 3 arguments 'HELLO=Hello World', 'echo' and '$HELLO'
• The env command will run and set the HELLO='Hello World' in its environment
• env will run echo with the argument '$HELLO'

In this case, there's no shell that will expand the $HELLO, so echo receives the string $HELLO and prints out that. Variable expansion is done by shells only.