How to iterate over function arguments

Question

I have a Python function accepting several string arguments def foo(a, b, c): and concatenating them in a string. I want to iterate over all function arguments

Answer 1

You can use the inspect module and define a function like that:

import inspect
def f(a,b,c):
    argspec=inspect.getargvalues(inspect.currentframe())
    return argspec
f(1,2,3)
ArgInfo(args=['a', 'b', 'c'], varargs=None, keywords=None, locals={'a': 1, 'c': 3, 'b': 2})

in argspec there are all the info you need to perform any operation with argument passed.

To concatenate the string is sufficient to use the arg info received:

def f(a,b,c):
    argspec=inspect.getargvalues(inspect.currentframe())
    return ''.join(argspec.locals[arg] for arg in argspec.args)

For reference: http://docs.python.org/library/inspect.html#inspect.getargvalues