Python 3 Building an array of bytes

Question

I need to build a tcp frame with raw binary data, but all examples and tutorials I\'ve found talking about bytes always involve conversion from a string, and that\'s not wha

Answer 1

Here is a solution to getting an array (list) of bytes:

I found that you needed to convert the Int to a byte first, before passing it to the bytes():

bytes(int('0xA2', 16).to_bytes(1, "big"))

Then create a list from the bytes:

list(frame)

So your code should look like:

frame = b""
frame += bytes(int('0xA2', 16).to_bytes(1, "big"))
frame += bytes(int('0x01', 16).to_bytes(1, "big"))
frame += bytes(int('0x02', 16).to_bytes(1, "big"))
frame += bytes(int('0x03', 16).to_bytes(1, "big"))
frame += bytes(int('0x04', 16).to_bytes(1, "big"))
bytesList = list(frame)

The question was for an array (list) of bytes. You accepted an answer that doesn't tell how to get a list so I'm not sure if this is actually what you needed.