TypeScript - Take object out of array based on attribute value

Question

My array looks like this:

array = [object {id: 1, value: \"itemname\"}, object {id: 2, value: \"itemname\"}, ...]

all my objects have the s

Answer 1

Below worked for me.

let array = [
    { id: 1, value: "itemname" },
    { id: 2, value: "itemname" }
];

let item1 = array.find(i => i.id === 1);