TypeScript - Take object out of array based on attribute value

Question

My array looks like this:

array = [object {id: 1, value: \"itemname\"}, object {id: 2, value: \"itemname\"}, ...]

all my objects have the s

Answer 1

I'd use filter or reduce:

let array = [
    { id: 1, value: "itemname" },
    { id: 2, value: "itemname" }
];

let item1 = array.filter(item => item.id === 1)[0];
let item2 = array.reduce((prev, current) => prev || current.id === 1 ? current : null);

console.log(item1); // Object {id: 1, value: "itemname"}
console.log(item2); // Object {id: 1, value: "itemname"}

(code in playground)

If you care about iterating over the entire array then use some:

let item;
array.some(i => {
    if (i.id === 1) {
        item = i;
        return true;
    }
    return false;
});

(code in playground)