Named capture groups with NSRegularExpression

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爱一瞬间的悲伤
爱一瞬间的悲伤 2020-12-29 00:05

Does NSRegularExpression support named capture groups? It doesn\'t look like it from the documentation, but I wanted to check before I explore alternative solut

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  •  粉色の甜心
    2020-12-29 00:49

    iOS 11 introduced named capture support using the -[NSTextCheckingResult rangeWithName:] API.

    To get a dictionary of named captures with their associated values you can use this extension (written in Swift, but can be called from Objective C):

    @objc extension NSString {
        public func dictionaryByMatching(regex regexString: String) -> [String: String]? {
            let string = self as String
            guard let nameRegex = try? NSRegularExpression(pattern: "\\(\\?\\<(\\w+)\\>", options: []) else {return nil}
            let nameMatches = nameRegex.matches(in: regexString, options: [], range: NSMakeRange(0, regexString.count))
            let names = nameMatches.map { (textCheckingResult) -> String in
                return (regexString as NSString).substring(with: textCheckingResult.range(at: 1))
            }
            guard let regex = try? NSRegularExpression(pattern: regexString, options: []) else {return nil}
            let result = regex.firstMatch(in: string, options: [], range: NSMakeRange(0, string.count))
            var dict = [String: String]()
            for name in names {
                if let range = result?.range(withName: name),
                    range.location != NSNotFound
                {
                    dict[name] = self.substring(with: range)
                }
            }
            return dict.count > 0 ? dict : nil
        }
    }
    

    Call from Objective-C:

    (lldb) po [@"San Francisco, CA" dictionaryByMatchingRegex:@"^(?.+), (?[A-Z]{2})$"];
    {
        city = "San Francisco";
        state = CA;
    }
    

    Code explanation: The function first needs to find out the list of named captures. Unfortunately, Apple didn't publish an API for that (rdar://36612942).

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