Bash script to get all IP addresses

Question

I am trying to write a bash script to get all IP addresses on a server. The script should work on all major distros. Here is what I have:

ifconf         


        

Answer 1

There's no need for grep. Here's one way using awk:

List only addr:

ifconfig | awk -F "[: ]+" '/inet addr:/ { if ($4 != "127.0.0.1") print $4 }'

List device and addr:

ifconfig | awk -v RS="\n\n" '{ for (i=1; i<=NF; i++) if ($i == "inet" && $(i+1) ~ /^addr:/) address = substr($(i+1), 6); if (address != "127.0.0.1") printf "%s\t%s\n", $1, address }'