Does C++ do value initialization of a POD typedef?

Question

Does C++ do value initialization on simple POD typedefs?

Assuming

typedef T* Ptr;

does

Ptr()

do v

Answer 1

#include 
struct Foo {
    char bar;
    char baz;
    char foobar;
    // the struct is a POD
    //virtual void a() { bar='b'; }
};

int main() {
    Foo o1;
    Foo o2 = Foo();

    std::cout << "O1: " << (int)o1.bar <<" "<< (int)o1.baz <<" "<< (int)o1.foobar << std::endl;
    std::cout << "O2: " << (int)o2.bar <<" "<< (int)o2.baz <<" "<< (int)o2.foobar << std::endl;
    return 0;
}

Output:

O1: -27 -98 0

O2: 0 0 0

Adding () propagates initializer calls to all POD members. Uncomenting the virtual method changes output to:

O1: -44 -27 -98

O2: -71 -120 4

However adding destructor ~Foo() does not suppress the initialization, although it creates non-POD object (output similar to first one).