How to create a directory and file in that directory using phonegap file api?

Question

I am using phonegap file api to create a directory and create a file in the directory created. The directory is getting created, but the file is not getting created in the d

Answer 1

function download(URL, fileName){
   var folderName = 'xyz';
   var uri = encodeURI(URL);

        window.requestFileSystem(LocalFileSystem.PERSISTENT, 0,
            function (fileSystem) {
                var directoryEntry = fileSystem.root; // to get root path of directory
                directoryEntry.getDirectory(folderName, {
                    create: true,
                    exclusive: false
                }, onDirectorySuccess, onDirectoryFail); 
                var filename = fileSystem.root.toURL() + folderName + "/" + uri.substr(uri.lastIndexOf("/") + 1);

                var fileTransfer = new FileTransfer();
                fileTransfer.download(uri, filename,
                    function(entry) { // download success
                        var path = entry.toURL(); //**THIS IS WHAT I NEED**
                        window.plugins.toast.showLongBottom("Download Completed: " + entry.fullPath, function (a) {
                        }, function (b) {
                        });
                    },
                    function(error) {
                        console.log("error")
                    } // irrelevant download error
                );`enter code here`
            },
            function(error) {
                console.log("error2")
            } // irrelevant request fileSystem error
        );

        function onDirectorySuccess(parent) {
            // Directory created successfuly
            console.log("Directory created successfuly: " + JSON.stringify(parent));
            var fp = (parent.nativeURL) + fileName;
            filetransfer(download_link, fp);
        }

        function onDirectoryFail(error) {
            //Error while creating directory
            alert("Unable to create new directory: " + error.code);
        }
    }