The standard way of intersecting two sets in C++ is to do the following:
std::set set_1; // With some elements
std::set set_2; // Wit
I think I've got it:
std::set::iterator it1 = set_1.begin();
std::set::iterator it2 = set_2.begin();
while ( (it1 != set_1.end()) && (it2 != set_2.end()) ) {
if (*it1 < *it2) {
set_1.erase(it1++);
} else if (*it2 < *it1) {
++it2;
} else { // *it1 == *it2
++it1;
++it2;
}
}
// Anything left in set_1 from here on did not appear in set_2,
// so we remove it.
set_1.erase(it1, set_1.end());
Anyone see any problems? Seems to be O(n) on the size of the two sets. According to cplusplus.com, std::set erase(position) is amortized constant while erase(first,last) is O(log n).