How to get concrete type of a generic interface

Question

I have an interface

public interface FooBar { }

I have a class that implements it

public class BarFoo implements Foo

Answer 1

Try something like the following:

Class thisClass = null;
Type type = getClass().getGenericSuperclass();
if (type instanceof ParameterizedType) {
    ParameterizedType parameterizedType = (ParameterizedType) type;
    Type[] typeArguments = parameterizedType.getActualTypeArguments();
    thisClass = (Class) typeArguments[0];
}