Printing Table's structure/schema

Question

I have like 20 or so tables in the database RentalEase and I want to print them out (physically) so I can look at them easier. I don\'t care too much about what data is in t

Answer 1

Here is a script I wrote that simply lists each table and their columns in a format like:

Table Columns

table1 column1,column2...columnX

The script is:

declare @max_tables int
declare @max_columns int
declare @sql nvarchar(400)
declare @x int
declare @y int
declare @table varchar(50)
declare @columns varchar(800)

create table #c ([Table] varchar(50),[Columns] varchar(800))

select ROW_NUMBER() OVER(ORDER BY name) AS Row, name 
into #table_list
from sys.objects 
where type_desc = 'USER_TABLE' 
order by name

set @max_tables = (select count(*) from sys.objects where type_desc = 'USER_TABLE')
set @y = 0

while @y < @max_tables
    begin
        set @y = @y + 1
        set @table = (select name from #table_list where row = @y)

        create table #t (c int)

        set @sql = 'select count(*) as c from Information_schema.Columns where table_name = ''' + @table + ''''
        insert into #t exec sp_executesql @sql

        set @max_columns = (select top 1 c from #t)

        DROP TABLE #t

        set @x = 0
        set @columns = ''

        while @x < @max_columns 
            begin
                set @x = @x + 1
                set @columns = @columns + (select column_name from Information_schema.Columns where table_name = @table and ordinal_position = @x)
                if @x < @max_columns set @columns = @columns + ', '
            end

        insert into #c select @table,@columns

    end

select * from #c

DROP TABLE #c
DROP TABLE #table_List