Implementing the copy constructor in terms of operator=

Question

If the operator= is properly defined, is it OK to use the following as copy constructor?

MyClass::MyClass(MyClass const &_copy)
{
    *this          


        

Answer 1

While the end result is the same, the members are first default initialized, only copied after that.

With 'expensive' members, you better copy-construct with an initializer list.

struct C {
   ExpensiveType member;

   C( const C& other ): member(other.member) {}
};



 };