Underscore: remove all key/value pairs from an array of object

Question

Is there a \"smart\" underscore way of removing all key/value pairs from an array of object?

e.g. I have following array:

var arr = [
        { q: \"         


        

Answer 1

You can use map and omit in conjunction to exclude specific properties, like this:

var newArr = _.map(arr, function(o) { return _.omit(o, 'c'); });

Or map and pick to only include specific properties, like this:

var newArr = _.map(arr, function(o) { return _.pick(o, 'q'); });