Why can't a data member be in a lambda capture list

Question

I have a class foo that has bar as a member variable.

In another member function of the class, I\'m writing a lambda function:

Answer 1

You capture class members by saying this in the capture list. This has nothing to do with the fact that the member is const.

---

Example:

#include 

struct Foo
{
    const int a = 0;
    int b;
    Foo() : b{42} {
        auto f = [this]() { std::cout << a << " " << b << std::endl; };
//                ^^^^ 
        f();
    }
};

int main() {
    Foo x;
}