How to extract last part of string in bash?

Question

I have this variable:

A="Some variable has value abc.123"

I need to extract this value i.e abc.123. Is this possible i

Answer 1

The documentation is a bit painful to read, so I've summarised it in a simpler way.

Note that the '*' needs to swap places with the '' depending on whether you use # or %. (The * is just a wildcard, so you may need to take off your "regex hat" while reading.)

• ${A%% *} - remove longest trailing * (keep only the first word)
• ${A% *} - remove shortest trailing * (keep all but the last word)
• ${A##* } - remove longest leading * (keep only the last word)
• ${A#* } - remove shortest leading * (keep all but the first word)

Of course a "word" here may contain any character that isn't a literal space.