Goto out of a block: do destructors get called?

Question

Consider the following code:

void foo()
{
    {
        CSomeClass bar;

        // Some code here...

        goto label;

        // and here...
    }

lab         


        

Answer 1

Yes, they will be called.

Update: (it's okay to do this, gotos is not worse than throwing dummy exceptions or using bools/ifs to get out of things. A simple goto inside a function don't make it spaghetti code.)