I am getting the impression that this is not possible in word but I figure if you are looking for any 3-4 words that come in the same sequence anywhere in a very long paper
I chose a rather lame theory, but it seems to work (at least if I got the question right cuz sometimes I'm a slow understander).
I load the entire text into a string, load the individual words into an array, loop through the array and concatenate the string, containing each time three consecutive words.
Because the results are already included in 3 word groups, 4 word groups or more will automatically be recognized.
Option Explicit
Sub Find_Duplicates()
On Error GoTo errHandler
Dim pSingleLine As Paragraph
Dim sLine As String
Dim sFull_Text As String
Dim vArray_Full_Text As Variant
Dim sSearch_3 As String
Dim lSize_Array As Long
Dim lCnt As Long
Dim lCnt_Occurence As Long
'Create a string from the entire text
For Each pSingleLine In ActiveDocument.Paragraphs
sLine = pSingleLine.Range.Text
sFull_Text = sFull_Text & sLine
Next pSingleLine
'Load the text into an array
vArray_Full_Text = sFull_Text
vArray_Full_Text = Split(sFull_Text, " ")
lSize_Array = UBound(vArray_Full_Text)
For lCnt = 1 To lSize_Array - 1
lCnt_Occurence = 0
sSearch_3 = Trim(fRemove_Punctuation(vArray_Full_Text(lCnt - 1) & _
" " & vArray_Full_Text(lCnt) & _
" " & vArray_Full_Text(lCnt + 1)))
With Selection.Find
.Text = sSearch_3
.Forward = True
.Replacement.Text = ""
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
Do While .Execute
lCnt_Occurence = lCnt_Occurence + 1
If lCnt_Occurence > 1 Then
Selection.Range.Font.Color = vbRed
End If
Selection.MoveRight
Loop
End With
Application.StatusBar = lCnt & "/" & lSize_Array
Next lCnt
errHandler:
Stop
End Sub
Public Function fRemove_Punctuation(sString As String) As String
Dim vArray(0 To 8) As String
Dim lCnt As Long
vArray(0) = "."
vArray(1) = ","
vArray(2) = ","
vArray(3) = "?"
vArray(4) = "!"
vArray(5) = ";"
vArray(6) = ":"
vArray(7) = "("
vArray(8) = ")"
For lCnt = 0 To UBound(vArray)
If Left(sString, 1) = vArray(lCnt) Then
sString = Right(sString, Len(sString) - 1)
ElseIf Right(sString, 1) = vArray(lCnt) Then
sString = Left(sString, Len(sString) - 1)
End If
Next lCnt
fRemove_Punctuation = sString
End Function
The code assumes a continuous text without bullet points.