The pandas factorize
function assigns each unique value in a series to a sequential, 0-based index, and calculates which index each series entry belongs to.
I am not sure if this is an efficient solution. There might be better solutions for this.
arr=[] #this will hold the unique items of the dataframe
for i in df.index:
if list(df.iloc[i]) not in arr:
arr.append(list(df.iloc[i]))
so printing the arr would give you
>>>print arr
[[1,1],[1,2],[2,2]]
to hold the indices, i would declare an ind array
ind=[]
for i in df.index:
ind.append(arr.index(list(df.iloc[i])))
printing ind would give
>>>print ind
[0,1,2,2,1,0]