Reading Geotag data from image in php

Question

Does anyone know if there is a way to read geotag data from photos in PHP?

Thanks

Answer 1

Call this function with filename. I testet it and it works prefectly.

Call example:

$fileName='xxxxxx'; //or $fileName='xxxxxxxxx';
echo $returned_data = triphoto_getGPS($fileName);

Function:

function triphoto_getGPS($fileName)
{
    //get the EXIF all metadata from Images
    $exif = exif_read_data($fileName);
    if(isset($exif["GPSLatitudeRef"])) {
        $LatM = 1; $LongM = 1;
        if($exif["GPSLatitudeRef"] == 'S') {
            $LatM = -1;
        }
        if($exif["GPSLongitudeRef"] == 'W') {
            $LongM = -1;
        }

        //get the GPS data
        $gps['LatDegree']=$exif["GPSLatitude"][0];
        $gps['LatMinute']=$exif["GPSLatitude"][1];
        $gps['LatgSeconds']=$exif["GPSLatitude"][2];
        $gps['LongDegree']=$exif["GPSLongitude"][0];
        $gps['LongMinute']=$exif["GPSLongitude"][1];
        $gps['LongSeconds']=$exif["GPSLongitude"][2];

        //convert strings to numbers
        foreach($gps as $key => $value){
            $pos = strpos($value, '/');
            if($pos !== false){
                $temp = explode('/',$value);
                $gps[$key] = $temp[0] / $temp[1];
            }
        }

        //calculate the decimal degree
        $result['latitude']  = $LatM * ($gps['LatDegree'] + ($gps['LatMinute'] / 60) + ($gps['LatgSeconds'] / 3600));
        $result['longitude'] = $LongM * ($gps['LongDegree'] + ($gps['LongMinute'] / 60) + ($gps['LongSeconds'] / 3600));
        $result['datetime']  = $exif["DateTime"];

        return $result;
    }
}