I\'ve come across the problem of maintaining a state throughout a map operation several times. Imagine the following task:
Given a List[Int], map each element to the
The scan answers are the best ones, but it's worth noting that one can make the fold look nicer and/or be shorter than in your question. First, you don't need to use pattern matching:
a.foldLeft(List(0)){ (l,i) => (l.head + i) :: l }.reverse
Second, note that foldLeft has an abbreviation:
(List(0) /: a){ (l,i) => (l.head + i) :: l }.reverse
Third, note that you can, if you want, use a collection that can append efficiently so that you don't need to reverse:
(Vector(0) /: a){ (v,i) => v :+ (v.last + i) }
So while this isn't nearly as compact as scanLeft:
a.scanLeft(0)(_ + _)
it's still not too bad.