I\'d like to define a custom application list to use in django\'s admin index page because I want the apps displayed in a specific order, rather than the default alphabetica
If you don't mind to use a subclass of django.contrib.admin.site.AdminSite(), as expected in cases when you need to customize your admin site, I think it's a feasible idea rewriting "index" and "app_index" methods in the derived class. You can do custom ordering using two dictionaries that store the app declararion order in settings.py and the registration order of models.
Then rewrite the code of the original AdminSite().index() and app_index(), adding a custom order fields ('order') in app_list and order by this field despite 'name'. This is the code, excluding app_index(), that is similar to index() function:
class MyAdminSite(AdminSite):
def __init__(self, name='admin', app_name='admin'):
super(MyAdminSite, self).__init__(name, app_name)
# Model's registration ordering. It's not necessary to
# categorize by app.
self._registry_ord = {}
# App ordering determined by declaration
self._app_ord = { 'auth' : 0 }
app_position = 1
for app in settings.INSTALLED_APPS:
self._app_ord[app] = app_position
app_position += 1
def register(self, model_or_iterable, admin_class=None, **options):
super(MyAdminSite, self).register(model_or_iterable, admin_class, **options)
if isinstance(model_or_iterable, ModelBase):
model_or_iterable = [model_or_iterable]
for model in model_or_iterable:
if model in self._registry:
if self._registry_ord:
self._registry_ord[model._meta.object_name] = max(self._registry_ord.values()) + 1
else:
self._registry_ord[model._meta.object_name] = 1
@never_cache
def index(self, request, extra_context=None):
"""
Displays the main admin index page, which lists all of the installed
apps that have been registered in this site.
"""
app_dict = {}
user = request.user
for model, model_admin in self._registry.items():
app_label = model._meta.app_label
has_module_perms = user.has_module_perms(app_label)
if has_module_perms:
perms = model_admin.get_model_perms(request)
# Check whether user has any perm for this module.
# If so, add the module to the model_list.
if True in perms.values():
info = (app_label, model._meta.module_name)
model_dict = {
'name': capfirst(model._meta.verbose_name_plural),
'perms': perms,
'order': self._registry_ord[model._meta.object_name]
}
if perms.get('change', False):
try:
model_dict['admin_url'] = reverse('admin:%s_%s_changelist' % info, current_app=self.name)
except NoReverseMatch:
pass
if perms.get('add', False):
try:
model_dict['add_url'] = reverse('admin:%s_%s_add' % info, current_app=self.name)
except NoReverseMatch:
pass
if app_label in app_dict:
app_dict[app_label]['models'].append(model_dict)
else:
app_dict[app_label] = {
'name': app_label.title(),
'app_url': reverse('admin:app_list', kwargs={'app_label': app_label}, current_app=self.name),
'has_module_perms': has_module_perms,
'models': [model_dict],
'order': self._app_ord[app_label],
}
# Sort the apps alphabetically.
app_list = app_dict.values()
app_list.sort(key=lambda x: x['order'])
# Sort the models alphabetically within each app.
for app in app_list:
app['models'].sort(key=lambda x: x['order'])
context = {
'title': _('Site administration'),
'app_list': app_list,
}
context.update(extra_context or {})
return TemplateResponse(request, [
self.index_template or 'admin/index.html',
], context, current_app=self.name)
If you use custom AdminSite and you want to include Auth models you probably need this, somewhere in your code (I made it in a specific app to extend user information :
from django.contrib.auth.models import User, Group
from myproject import admin
admin.site.register(User)
admin.site.register(Group)