In Scala, can generic type parameters be used with *function* definitions?

Question

Is there a syntax to allow generic type parameters on function literals? I know I could wrap it in a method such as:

def createLongStringFunction[T](): (T) =         


        

Answer 1

Since longStringFunction defined as followed is a value, which must have some given type.

val longStringFunction: (T) => Boolean = (obj: T) => obj.toString.length > 7

However, you can reuse a function object with a method:

scala> val funObj: Any => Boolean = _.toString.size > 7
funObj: Any => Boolean = 

scala> def typedFunction[T]: T => Boolean = funObj
typedFunction: [T]=> T => Boolean

scala> val f1 = typedFunction[String]
f1: String => Boolean = 

scala> val f2 = typedFunction[Int]
f2: Int => Boolean = 

scala> f1 eq f2
res0: Boolean = true

This works because trait Function1[-T1, +R] is contravariant of type T1.