How can a stack underflow happen in C++?

Question

What is a simple example in C++ that causes a stack underflow in the case of invoking and returning from method calls?

I am familiar with the calling convention, i.e

Answer 1

Normally this would be taken care of by the compiler. In reality, the only way I can think of that you could accidentally cause a stack underflow would be by calling a method implemented with one calling convention as if it was using another calling convention.