Different Pointer Arithmetic Results when Taking Address of Array

Question

Program:

#include

int main(void) {
    int x[4];
    printf(\"%p\\n\", x);
    printf(\"%p\\n\", x + 1);
    printf(\"%p\\n\", &x);
    p         


        

Answer 1

An easy thumbrule to evaluate this is:

Any pointer on increment points to the next memory location of its base type.

The base type of &x here is int (*p)[4] which is a pointer to array of 4 integers.

So the next pointer of this type will point to 16 bytes away (assuming int to be 4 bytes) from the original array.