How to get offset() relative to parent in jQuery?

前端 未结 4 867
无人共我
无人共我 2020-12-25 09:37

This gives me the position of some element from the left edge of the main window:

$(\'#bar\').offset().left;

If that element is situated in

4条回答
  •  再見小時候
    2020-12-25 10:31

    It's simple enough: get the offset of the element and substract the offset of its parent.

    var elem = $("#bar");
    var offset = elem.offset().left - elem.parent().offset().left;
    

提交回复
热议问题