What is the equivalent of “zip()” in Python's numpy?

Question

I am trying to do the following but with numpy arrays:

x = [(0.1, 1.), (0.1, 2.), (0.1, 3.), (0.1, 4.), (0.1, 5.)]
normal_result = zip(*x)

Answer 1

You can just transpose it...

>>> a = np.array([(0.1, 1.), (0.1, 2.), (0.1, 3.), (0.1, 4.), (0.1, 5.)])
>>> a
array([[ 0.1,  1. ],
       [ 0.1,  2. ],
       [ 0.1,  3. ],
       [ 0.1,  4. ],
       [ 0.1,  5. ]])
>>> a.T
array([[ 0.1,  0.1,  0.1,  0.1,  0.1],
       [ 1. ,  2. ,  3. ,  4. ,  5. ]])