Find a special number in an array

Question

There are many numbers in an array and each number appears three times excepting for one special number appearing once. Here is the question: how can I find the special numb

Answer 1

I got a solution. It's O (n) time and O (1) space.

n=list(map(int,input().split()))
l=[0]*64
for x in n:
    b=bin(x)[2:]
    b='0'*(64-len(b))+b
    i=0
    while i