What is page table entry size?

Question

I found this example.

Consider a system with a 32-bit logical address space. If the page size in such a system is 4 KB (2^12), then a page table may

Answer 1

1. Your first doubt is in the line, "Each entry in the Page Table Entry, also called PTE, consists of 4 bytes". To understand this, first let's discuss what does page table contain?", Answer will be PTEs. So,this 4 bytes is the size of each PTE which consist of virtual address, offset,( And maybe 1-2 other fields if are required/desired)

2. So, now you know what page table contains, you can easily calculate the memory space it will take, that is: Total no. of PTEs times the size of a PTE. Which will be: 1m * 4 bytes= 4MB Hope this clears your doubt. :)