Bash: sort text file by last field value

Question

I have a text file containing ~300k rows. Each row has a varying number of comma-delimited fields, the last of which is guaranteed numerical. I want to sort the file by this

Answer 1

I'm going to throw mine in here as an alternative (and I couldn't get awk to work) :)

sample file:

Call of Doody                           1322
Seam the Ripper                         1329
Mafia Bots 1                            1109
Chicken Fingers                         1243
Batup Light                             1221
Hunter F Tomcat                         1140
Tober                                   0833

code:

for i in `sed -e 's/.* \(\d\)*/\1/' file.txt | sort`; do grep $i file.txt; done > file_sort.txt