Scala/Play: parse JSON into Map instead of JsObject

Question

On Play Framework\'s homepage they claim that \"JSON is a first class citizen\". I have yet to see the proof of that.

In my project I\'m dealing with some pretty co

Answer 1

For further reference and in the spirit of simplicity, you can always go for:

Json.parse(jsonString).as[Map[String, JsValue]]

However, this will throw an exception for JSON strings not corresponding to the format (but I assume that goes for the Jackson approach as well). The JsValue can now be processed further like:

jsValueWhichBetterBeAList.as[List[JsValue]]

I hope the difference between handling Objects and JsValues is not an issue for you (only because you were complaining about JsValues being proprietary). Obviously, this is a bit like dynamic programming in a typed language, which usually isn't the way to go (Travis' answer is usually the way to go), but sometimes that's nice to have I guess.