Remove last argument from argument list of shell script (bash)

Question

This question concerns a bash script that is run in automator osx. I am using automator actions to get and filter a bunch of file references from the finder. Then I append t

Answer 1

Assuming that you already have an array, you can say:

unset "array[${#array[@]}-1]"

---

For example, if your script contains:

array=( "$@" )
unset "array[${#array[@]}-1]"    # Removes last element -- also see: help unset
for i in "${array[@]}"; do
  echo "$i"
done

invoking it with: bash scriptname foo bar baz produces:

foo
bar