Django dynamic forms - on-the-fly field population?

Question

I\'ve been scanning through Django documentation, and Google search results, all afternoon and I\'m still somewhat stuck in my attempt to create a dynamic form. I\'m hoping

Answer 1

I do a similar thing here, populating a form based on a selection in a drop down. Maybe this helps you.

Here is the model of the values used to pre-populate the form:

class OpmerkingenGebrek(models.Model):
    opmerking = models.CharField(max_length=255)
    advies = models.CharField(max_length=255)
    urgentiecodering = models.CharField(max_length=2, choices=URGENTIE_CHOICES_2011)
    bepaling = models.CharField(max_length=155,blank=True,null=True)
    aard = models.CharField(max_length=3, choices=AARD_CHOICES)

The view that manages the form:

def manage_component(request,project_id,.....):
    # get values for pre-populate
    og = OpmerkingenGebrek.objects.all()
    .........
    formset = ComponentForm(request.POST,request.FILES)
    .........
        )))
    return render_to_response(template, {
        'formset':formset,
        ........
        'og':og,
        },context_instance=RequestContext(request))

The html the renders the form

{% extends "base.html" %}
{% block extra_js %}


{% endblock %}

{{ formset.as_table }}


Choose default values:

    {% for i in og %}
    {{ i.opmerking }}
    {% endfor %}

The javascript that pre-populates the form:

function getValue(sel)

  {
    //get values
    var opm = sel.options[sel.selectedIndex].value;
    //split string to parts
    var parts = opm.split("|");
    // autofill form
    var opmerking = document.getElementById("id_opmerking");
    opmerking.value = parts[0];
    var aanbeveling = document.getElementById("id_aanbeveling");
    aanbeveling.value = parts[1];
    var opt = document.getElementById("id_urgentie");
    var urgentie = opt.selectedIndex;
    for(var i=0;i