error: invalid type argument of ‘unary *’ (have ‘int’)

Question

I have a C Program:

#include 
int main(){
  int b = 10;             //assign the integer 10 to variable \'b\'

  int *a;                 //dec         


        

Answer 1

I have reformatted your code.

The error was situated in this line :

printf("%d", (**c));

To fix it, change to :

printf("%d", (*c));

The * retrieves the value from an address. The ** retrieves the value (an address in this case) of an other value from an address.

In addition, the () was optional.

#include 

int main(void)
{
    int b = 10; 
    int *a = NULL;
    int *c = NULL;

    a = &b;
    c = &a;

    printf("%d", *c);

    return 0;
} 

EDIT :

The line :

c = &a;

must be replaced by :

c = a;

It means that the value of the pointer 'c' equals the value of the pointer 'a'. So, 'c' and 'a' points to the same address ('b'). The output is :

10

EDIT 2:

If you want to use a double * :

#include 

int main(void)
{
    int b = 10; 
    int *a = NULL;
    int **c = NULL;

    a = &b;
    c = &a;

    printf("%d", **c);

    return 0;
} 

Output:

10