Rounding time in Python

Question

What would be an elegant, efficient and Pythonic way to perform a h/m/s rounding operation on time related types in Python with control over the rounding resolution?

Answer 1

This will round up time data to a resolution as asked in the question:

import datetime as dt

current = dt.datetime.now()
current_td = dt.timedelta(hours=current.hour, minutes=current.minute, seconds=current.second, microseconds=current.microsecond)

# to seconds resolution
to_sec = dt.timedelta(seconds=round(current_td.total_seconds()))
print(dt.datetime.combine(current, dt.time(0)) + to_sec)

# to minute resolution
to_min = dt.timedelta(minutes=round(current_td.total_seconds() / 60))
print(dt.datetime.combine(current, dt.time(0)) + to_min)

# to hour resolution
to_hour = dt.timedelta(hours=round(current_td.total_seconds() / 3600))
print(dt.datetime.combine(current, dt.time(0)) + to_hour)