C++ function returning function

Question

Where in the standard are functions returning functions disallowed? I understand they are conceptually ridiculous, but it seems to me that the grammar would allow them. Acco

Answer 1

in kinda sense,function_pointer is funciton its self,
and "trailing return type" is a good and hiding thing in c++11,i will rather write like this:

#include



auto return0(void)->int
{return 0;}
auto returnf(void)->decltype(&return0)
{return &return0;}



/*Edit: or...
auto returnf(void)->auto (*)(void)->int
{return &return0;}
//that star means function pointer
*/




auto main(void)->int
{
    std::cout<

(if type unmatch,try apply address operator "&")
look,so much of sense.

but down side of this is that "auto" thing in head of function,
that`s non-removable and no type could match it (even lambda could match template type std::function<>) but if you wish,macro could do magic(sometime curse) to you

#define func auto