Opposite of set.intersection in python?

Question

In Python you can use a.intersection(b) to find the items common to both sets.

Is there a way to do the disjoint opposite version of this? Ite

Answer 1

Try this code for (set(a) - intersection(a&b))

a = [1,2,3,4,5,6]
b = [2,3]

for i in b:
   if i in a:
      a.remove(i)

print(a)

the output is [1,4,5,6] I hope, it will work