Pairwise circular Python 'for' loop

Question

Is there a nice Pythonic way to loop over a list, retuning a pair of elements? The last element should be paired with the first.

So for instance, if I have the list

Answer 1

This is my solution, and it looks Pythonic enough to me:

l = [1,2,3]

for n,v in enumerate(l):
    try:
        print(v,l[n+1])
    except IndexError:
        print(v,l[0])

prints:

1 2
2 3
3 1

The generator function version:

def f(iterable):
    for n,v in enumerate(iterable):
        try:
            yield(v,iterable[n+1])
        except IndexError:
            yield(v,iterable[0])

>>> list(f([1,2,3]))
[(1, 2), (2, 3), (3, 1)]