How to go from CMutablePointer to CGFloat[] in Swift

Question

I am trying to convert an ObjC class that uses Facebook\'s pop library to Swift. Pop uses quite a bit of C.

In ObjC, I have a block that looks like this...

Answer 1

EDIT: Just wanted to clarify a few things after learning a bit more from the online documentation (PDF).

There are a few commonly used pointer types in Swift, here is how they map to C equivalents:

Pointers as Arguments

CConstVoidPointer     => const void *
CMutableVoidPointer   => void *
CConstPointer   => const Type * 
CMutablePointer => Type *

Pointers as Return Types, Variables, and Arguments*

COpaquePointer      => void *
UnsafePointer => Type *

NOTE: Arguments follow this rule only when they are more than one pointer level deep, otherwise see above.

Pointers for Class Types

CConstPointer              => Type * const *
CMutablePointer            => Type * __strong *
AutoreleasingUnsafePointer => Type **

Swift Pointers

When using the CConstPointer pointer in Swift, you may pass any one of these:

• nil, which will be evaluated as a NULL pointer
• A CConstPointer value
• A CConstVoidPointer value
• A CMutablePointer value
• A CMutableVoidPointer
• A AutoreleasingUnsafePointer value which will be converted to CConstPointer if necessary
• A Type value passed by address (& operator)
• A Type[] array

NOTE:CConstVoidPointer can take any of the above values as well.

When using the CMutablePointer pointer in Swift, you may pass any one of these:

• nil, which will be evaluated as a NULL pointer
• A CMutablePointer value
• A Type value passed by address (& operator)
• A Type[] array passed by address (& operator)

NOTE:CMutableVoidPointer can take any of the above in addition to CMUtableVoidPointer values.

So it would seem in your case that a CMutablePointer could also be a pointer to an array of CGFloat values. Though I am not completely sure how to dereference that in Swift. (Perhaps the as operator?)