How can I expose iterators without exposing the container used?

Question

I have been using C# for a while now, and going back to C++ is a headache. I am trying to get some of my practices from C# with me to C++, but I am finding some resistance a

Answer 1

This should do what you want:

typedef typename std::vector::iterator MyIterator;

From Accelerated C++:

Whenever you have a type, such as vector, that depends on a template parameter, and you want to use a member of that type, such as size_type, that is itself a type, you must precede the entire name by typename to let the implementation know to treat the name as a type.