Understanding the Java stack

Question

There is this code:

public class Main {
    public static void main(final String[] args) throws Exception {
        System.out.print(\"1\");
        doAnythi         


        

Answer 1

One thing is clear that System.out.print("y"); in catch creates this puzzle. If we change the code as

static int n;

public static void main(final String[] args) throws Exception {
    System.out.println("1");
    doAnything();
    System.out.println(n);
}

private static void doAnything() {
    try {
        doAnything();
    } catch (Error e) {
        n++;
    }
}

it prints

1
1