How to extract elements from a list with mixed elements

Question

I have a list in R with the following elements:

[[812]]
[1] \"\"             \"668\"          \"12345_s_at\" \"667\"          \"4.899777748\" 
[6] \"49.53333         


        

Answer 1

With purrr you can extract elements and ensure data type consistency:

library(purrr)

listdata <- list(c("","668","12345_s_at","667", "4.899777748","49.53333333",
       "10.10930207", "1.598228663","5.087437057"),
     c("","376", "6789_at",  "375",  "4.899655078","136.3333333",
       "27.82508792", "2.20223398",  "5.087437057"),
     c("", "19265", "12351_s_at", "19264", "4.897730912",
       "889.3666667", "181.5874908","1.846451572","5.087437057" ))

map_chr(listdata, 3)
## [1] "12345_s_at" "6789_at"    "12351_s_at"

There are other map_ functions that enforce the type consistency as well and a map_df() which can finally help end the do.call(rbind, …) madness.