Default implementation of a method for C# interfaces?

Question

Is it possible to define an interface in C# which has a default implementation? (so that we can define a class implementing that interface without implementing that particul

Answer 1

As a newbe C# programmer I was reading through this topic and wondered if the following code example could be of any help (I don't even know if this is the proper way to do it). For me it allows me to code default behavior behind an interface. Note that I used the generic type specifiction to define an (abstract) class.

namespace InterfaceExample
{
    public interface IDef
    {
        void FDef();
    }

    public interface IImp
    {
        void FImp();
    }

    public class AbstractImplementation where T : IImp
    {
        // This class implements default behavior for interface IDef
        public void FAbs(IImp implementation)
        {
            implementation.FImp();
        }
    }

    public class MyImplementation : AbstractImplementation, IImp, IDef
    {
        public void FDef()
        {
            FAbs(this);
        }
        public void FImp()
        {
            // Called by AbstractImplementation
        }
    }

    class Program
    {
        static void Main(string[] args)
        {
            MyImplementation MyInstance = new MyImplementation();

           MyInstance.FDef();
        }
    }
}