How would you write a @debuggable decorator in python?

Question

When debugging, I like to print out all the inputs and outputs of a function (I know I need a better IDE, but humour me, this could be used for error reporting). So, I\'d id

Answer 1

You can use as decorator for debug; (@debug)

def debug(func):
    import functools

    @functools.wraps(func)
    def wrapper_debug(*args, **kwargs):
        args_repr = [repr(a) for a in args]  # 1
        kwargs_repr = [f"{k}={v!r}" for k, v in kwargs.items()]  # 2
        signature = ", ".join(args_repr + kwargs_repr)  # 3
        print(f"Call {func.__name__}({signature})")
        value = func(*args, **kwargs)
        print(f"{func.__name__!r} return {value!r}")  # 4
        return value

    return wrapper_debug