How would you write a @debuggable decorator in python?

Question

When debugging, I like to print out all the inputs and outputs of a function (I know I need a better IDE, but humour me, this could be used for error reporting). So, I\'d id

Answer 1

Use a debugger. Seriously. Decorating every function you want to keep track is a bad idea.

Python has a debugger included, so you don't need a good IDE.

If you don't want to use a debugger, you can use the trace function.

import sys

@sys.settrace
def trace_debug(frame, event, arg):
    if event == 'call':
        print ("calling %r on line %d, vars: %r" % 
                (frame.f_code.co_name, 
                 frame.f_lineno,
                 frame.f_locals))
        return trace_debug
    elif event == "return":
        print "returning", arg

def fun1(a, b):
    return a + b

print fun1(1, 2)

That prints:

calling 'fun1' on line 14, vars: {'a': 1, 'b': 2}
returning 3
3

Even easier would be to use Winpdb:

It is a platform independent graphical GPL Python debugger with support for remote debugging over a network, multiple threads, namespace modification, embedded debugging, encrypted communication and is up to 20 times faster than pdb.

Features:

• GPL license. Winpdb is Free Software.
• Compatible with CPython 2.3 or later.
• Compatible with wxPython 2.6 or later.
• Platform independent, and tested on Ubuntu Gutsy and Windows XP.
• User Interfaces: rpdb2 is console based, while winpdb requires wxPython 2.6 or later.

_{(source: winpdb.org)}